设fn∈M(X)(n=1,2,)几乎处处有限,则{fn}测度收敛σ>0;μX(|fm-fn|≥σ)→0(m,n→∞)
问答题设μX<∞,fn∈M(X),fn→∞,a.e.则,δ>0,XδX,使
问答题设f:R→R可测,f(x+y)=f(x)+f(y),则f(x)=ax