找考题网-背景图
单项选择题

已知燃气的容积成分为:yCO2=5.7%,yCmHn=5.3%,yO2=1.7%,yCO=8.4%,yH2=20.93%,yCH4=18.27%,yN2=39.7%。则该燃气火焰传播极限为()(CmHn按C3H6计算)。(惰性气体与可燃气体混合比为1.589和0.678时,火焰的传播极限分别为11%~75%和22%~68%;未与惰性气体组合的甲烷的火焰传播极限为5.0%~15%,未与惰性气体组合的C3H3的火焰传播极限为2.0%~11.7%)

A.7.74%~35.31%
B.13.5%~88%
C.40%~73.5%
D.19%~71%