Companycom has a requirement to consolidate six web app……

单项选择题Companycomhasrestoredtheirmksysb.Theynoticethattheexternalvolumegroupscannotbeseen.Whatshouldbedonetoaccessthevolumegroups?（）

A.Run importvg command
B.Run synclvodm command
C.Recreate volume groups
D.Update /etc/filesystems

单项选择题A solution for two batch applications was proposed in Companycom meeting. They are currently running in two LPARs on a p690. On a daily basis, both applications use 15% of the machine for their workload, and increase to 100% when their weekly reports are run. Since the reports are not run on the same day, what is the best solution?（）

A.COD
B.DLPAR
C.One big LPAR
D.Two separate p690 machines

单项选择题Ap5595doesnothaveanydeviceconnectedtoitforbackup.WhatAIXmethodshouldbeusedtobackupeachoftheLPARenvironmentsandhaveaquickrecoverypath?（）

A.Use savevg and copy to an NFS filesystem
B.Create a mksysb on an NFS exported filesystem
C.Use tar to copy system over network with a pipe
D.Create mksysb on an NFS exported NIM filesystem

单项选择题Companycom is planning a p5 595 running AIX 5L 5.3 LPARs. They would like to design the system using physical resources with maximum resource efficiency. One LPAR requires a peak load of 30 processors during the week with a low of 1 processor required on the weekend. The other LPAR requires only a single processor most of the time, but needs at least 24 processors at the beginning of the weekend to finish its weekly processing in the window allocated. Which of the following solutions is most appropriate to continuously maximize resource use for these two LPARs?（）

A.Dynamic LPAR
B.Workload Manager
C.Partition Load Manager
D.Shared Processor Pools

单项选择题An administrator has set up three partitions using a shared processor pool with 2 processors and SMT turned on. The partitions are activated in the following sequence: Partition one: Min = 0.5, max = 3.0, desired = 1.0; Partition two: Min = 1.0, max = 3.0, desired = 1.5 Partition three: Min = 1, max = 0.5, desired = 2. What is the outcome?（）

A.Partition one starts and has 3.0 logical processors. Partition two does not start. Partition three has 1.0 logical processors. 
B.Partition one starts and has 1.5 logical processors. Partition two has 1.0 logical processors. Partition three has 0.1 processors. 
C.Partition one starts and has 2.0 logical processors. Partition two start and has 2.0 logical processors. Partition three does not start. 
D.Partition one starts and has 2.0 logical processors. Partition two has 1.0 logical processors. Partition three has 0.1 logical processors.