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Identify three valid host addresses in the 192.168.27.0……

Identify three valid host addresses in the 192.168.27.0 network with a subnet mask of 255.255.255.240. ()

A.192.168.27.33
B.192.168.27.112
C.192.168.27.119
D.192.168.27.126
E.192.168.27.175
F.192.168.27.208

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